-0.075x^2+9.5x+50=0

Solution for -0.075x^2+9.5x+50=0 equation:

-0.075x^2+9.5x+50=0

a = -0.075; b = 9.5; c = +50;
Δ = b2-4ac
Δ = 9.52-4·(-0.075)·50
Δ = 105.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.5)-\sqrt{105.25}}{2*-0.075}=\frac{-9.5-\sqrt{105.25}}{-0.15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.5)+\sqrt{105.25}}{2*-0.075}=\frac{-9.5+\sqrt{105.25}}{-0.15}
$